**SQUARE ANY NUMBER USING VEDIC MATH**

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**Hello Everyone,**

I hope you are having fun with math using Vedic mathematics technique, in my previous post we learned multiplication tricks and witnessed that how easily we can solve complex multiplication problems using Vedic math. Knowledge to execute fast mental mathematical calculation will help us enormously regardless of which field of life our deal with. The significance of these mental math tricks is that it will give us positive edge over others irrespective of whether we are a student or a teacher.

In this blog post, we will learn how to find a square of any number using **Vedic math technique.**

**Now we will see the how we can implement Vedic technic and find the square of numbers ending with unit place digit as 5 (up to 95) in specific method.**

__Type 1: Square of any number with 5__

** 25 ^{2}**

1)2 is in ten’s place 5 is in unit’s place

2) Splits the digit

3) Tens place is 2 the next number of 2 is 3 multiply it i.e.2×3=6

4) Square of 5 is 25

5) Step 3 & step 4 together gives the final answer i.e.625

__Type 2: Square of any number with 25__

** 425 ^{2}**

1) Split two digits, hundred’s place 4 & ten’s and unit’s place is 25

2) Square hundred’s place i.e.4^{2} = 16

3) Square of 25^{2} = 625

4) Then divide 4/2=2

5) Add 16+2=18

6) Multiply 18 by 10 we will i.e. 18×10=180

7) Step 3 & step 6 together gives final answer i.e. 180,625

**Type 3: Square of any number lies between (30-80)**

** 53 ^{2}**

1)5 is ten place (Left side) & 3 is in unit place (Right side)

2) Consider the base, here 50 is nearest which can be taken as a Power of 10

3) Deviate the Number i.e. 53= (50+3) (Base + n)

4) Take the half of the base and add the digit of deviation ‘n’ i.e. 25+3=28

5) Square unit place (Right side) i.e. 3^{2}=9, When we take square of right side, if we get 1-digit value then we have to consider the value as 0 & the digit hence the value will be 09

6) Step 4 & Step 5 together gives the answer i.e. = 2,809

**Type 4**: **Square of any number to Base 100**

** 98 ^{2}**

1) Consider the base, here 100 is nearest base which can be taken as a power of 10

2) Deviate the number i.e. 98= (100-2) (Base-n)

3) Then 98-2=96

4) (n ^{2}) i.e. 2^{2}=4, if we get 1-digit value then we have to consider the value as 0 & the digit then the value will be 04

5) Step 3 & step 4 together gives the answer i.e. 9604

**Type 5: Square of any number near to Base n×100 **

** 896 ^{2}**

1) Consider the base, here 900 is nearest base which can be taken as a power of 10

2) Find the deviation for the given digits i.e. 896^{2}= (900-4)^{2}

3) We will split Base as (9×100 – 4) (n×100-n 1)

4) Multiply the given digit with n i.e. 896×9=8064

5) n×(-n 1) =9× (-4) =-36

6) Step 4-Step 3 i.e.8064-36=8028

7) Square n 1 i.e.4^{2}=16

8) Step 6 & Step 7 together gives the answer i.e. 802816

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Some of us might find it difficult when we just see these steps, with just a little bit of practice we can easily master these tricks and perform these simple math tricks in blink of an eye. In the below video I have solved few problems based on the above stated steps and I hope after seeing the video you find this technic simple and easy.

Thanks for stopping by.